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@ -263,7 +263,7 @@ This sequence number encoding allows for values above 999999, so care should be
4. Let $h$ be integer formed by the lower 31 bits of `digest2` 4. Let $h$ be integer formed by the lower 31 bits of `digest2`
5. Compute `digest1 = SHA1(5D || m || h || a || 00 00)` 5. Compute `digest1 = SHA1(5D || m || h || a || 00 00)`
6. Let $e$ be the integer formed by the lower 62 bits of `digest1` 6. Let $e$ be the integer formed by the lower 62 bits of `digest1`
7. Let $s = \frac{-ek + \sqrt{\left(ek\right)^2 + 4c}}{2} \pmod {n}$ 7. Let $s = \frac{ek + \sqrt{\left(ek\right)^2 + 4c}}{2} \pmod {n}$
8. Compute $a$ by unknown algorithm 8. Compute $a$ by unknown algorithm
9. Pack $s$, $h$, and $m$, and $a$ into a 114-bit integer 9. Pack $s$, $h$, and $m$, and $a$ into a 114-bit integer
10. Convert this integer into a product key, using base-24 conversion 10. Convert this integer into a product key, using base-24 conversion