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@ -279,10 +279,12 @@ Afterwards, the value $a$, along with some other information, can be sent to the
2. Compute the random point $R = cG$ 2. Compute the random point $R = cG$
3. Let `digest2 = SHA1(79 || m || R.x || R.y)` 3. Let `digest2 = SHA1(79 || m || R.x || R.y)`
4. Let $h$ be integer formed by the lower 31 bits of `digest2` 4. Let $h$ be integer formed by the lower 31 bits of `digest2`
5. Let $s = \frac{-ek + \sqrt{\left(ek\right)^2 + 4c}}{2} \pmod {n}$ 5. Compute `digest1 = SHA1(5D || m || h || a || 00 00)`
6. Compute $a$ by unknown algorithm 6. Let $e$ be the integer formed by the lower 62 bits of `digest1`
7. Pack $s$, $h$, and $m$, and $a$ into a 114-bit integer 7. Let $s = \frac{-ek + \sqrt{\left(ek\right)^2 + 4c}}{2} \pmod {n}$
8. Convert this integer into a product key, using base-24 conversion 8. Compute $a$ by unknown algorithm
9. Pack $s$, $h$, and $m$, and $a$ into a 114-bit integer
10. Convert this integer into a product key, using base-24 conversion
#### Mathematical mechanism #### Mathematical mechanism